-6x^2+96x+0=0

Solution for -6x^2+96x+0=0 equation:

-6x^2+96x+0=0

We add all the numbers together, and all the variables

-6x^2+96x=0

a = -6; b = 96; c = 0;
Δ = b2-4ac
Δ = 962-4·(-6)·0
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-96}{2*-6}=\frac{-192}{-12}
=+16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+96}{2*-6}=\frac{0}{-12}
=0
$